Apabila diketahui Ksp L(OH)3 = 2,7 x 10^-5 maka pH larutan jenuh L(OH3) adalah
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Apabila diketahui Ksp L(OH)3 = 2,7 x 10^-5 maka pH larutan jenuh L(OH3) adalah
2 Jawaban
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1. Jawaban AC88
Ksp L(OH)₃ = 27s⁴
2.7 . 10⁻⁵ = 27s⁴
s⁴ = 10⁻⁶
s = 10⁻³/₂
OH⁻ = 3s = 3 . 10⁻³/₂ M
pOH = 1.5 - log 3
pH = 12.5 + log 3 ~ 12.977 ⇒ Jawab -
2. Jawaban whongaliem
L(OH)3 ⇒ L+ + 3 .OH-
s s 3s
Ksp = (s)(3s)³
2,7 x 10^ -5 = s (27 s³)
2,7 x 10^ -5 = 27 s^4
s^4 = (2,7 x 10^ -5) / 27
s^4 = 10^ -6
s = 10^ (3/2)
[OH-] = 3 s
= 3 x 10^ ( -3/2)
POH = - log [OH-]
= - log (3 x 10^ - 3/2)
= 3/2 - log 3
PH = 14 - (3/2 - log 3)
= 12,5 + log 3