Diketahui vektor a=pi+3j-k dan b=4i-2j+2k saling tegak lurus. Vektor 3a-2b = ....

Vektor a tegak lurus b, Maka

[tex] \frac{}{a}* \frac{}{b} = 0 [/tex]

[tex] \left[\begin{array}{ccc}p\\3\\-1\end{array}\right] * \left[\begin{array}{ccc}4\\-2\\2\end{array}\right] = 0[/tex]

(p×4)+(3×-2)+(-1×2) = 0
4p - 6 - 2 = 0
4p - 8 = 0
4p = 8
p = 8/4
p = 2

Maka untuk vektor 3a - 2b :

[tex] 3 \left[\begin{array}{ccc}2\\3\\-1\end{array}\right] - 2 \left[\begin{array}{ccc}4\\-2\\2\end{array}\right] [/tex]

[tex] = \left[\begin{array}{ccc}6\\9\\-3\end{array}\right] - \left[\begin{array}{ccc}8\\-4\\4\end{array}\right] [/tex]

[tex] = \left[\begin{array}{ccc}-2\\13\\-7\end{array}\right][/tex]

atau :

[tex] = -2i+13j-7k[/tex]