Matematika

Pertanyaan

nilai maksimum dan minimum fungsi f(x)= x^³-3x^2-9x berturut adalah

1 Jawaban

  • TURUNAN

    f'(x) = 0
    3x^2 - 6x - 9 = 0
    x^2 - 2x- 3 = 0
    (x - 3)(x + 1) = 0
    x = 3 ; x = -1

    uji turunan kedua
    f"(x) = 6x - 6
    f"(3) = 6×3 - 6 = 18 - 6 = 12 > 0 (Minimum)

    fmin = f(3)
    => 3^3 - 3×3^2 - 9×3
    => 27 - 27 - 27
    => -27

    f"(-1) = 6×-1 - 6 = -6 - 6 = -12 < 0 (maks)
    fmaks = (-1)^3 - 3×(-1)^2 - 9×(-1) = -1-3+9 = 5

Pertanyaan Lainnya