Koordinat cartesiusnya p(-2akar2,2akar2)

R = akar x kuadrat + y kuadrat
= akar (-2 akar 2 kuadrat+ 2 akar 2 kuadrat )
= akar 4 . 2 +4 . 2
= akar 16
= akar 4 . 4
= 2 akar 4
tan a = y /x
= -2 akar 2 / 2 akar 2
= - 1
a = 150 drajat

P(-2√2, 2√2) = (x, y) => dikuadran 2
r = √(x^2 + y^2) = √((-2√2)^2 + (2√2)^2) = √(8 + 8) = √16 = 4
tan a = y/x = (2√2)/(-2√2) = -1 => Tan 135° => a = 135°
Koordinat kutub nya (4, 135°)