Matematika

Pertanyaan

Titik A(3,2,-1),B(1,-2,1) dan C(7,p-1,-5) segaris unuk nilai p=

2 Jawaban

  • langsung aja ya

    (p-1 - (-2))/(-2-2) = (7-1)/(1-3)
    (p - 1 + 2)/(-4) = 6/(-2)
    (p + 1)/(-4) = -3
    p + 1 = -3×-4
    p + 1 = 12
    p = 12 - 1
    p = 11
  • Jika A, B, dan C segaris maka berlaku :
    AB = k BC
    (b - a) = k (c - b)
    (1, -2, 1) - (3, 2, -1) = k ((7, p - 1, -5) - (1, -2, 1))
    (-2, -4, 2) = k (6, p + 1, -6)
    (-2, -4, 2) = (6k, (p + 1)k, -6k)
    6k = -2 => k = -2/6 => k = -1/3

    (p + 1)k = -4
    (p + 1) . -1/3 = -4
    p + 1 = 12
    p = 11

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