Titik potong kurva parabol y = x(x-6) dengan kurva y = x(x-3)(x-6)
Matematika
ilhamlira36
Pertanyaan
Titik potong kurva parabol y = x(x-6) dengan kurva y = x(x-3)(x-6)
1 Jawaban
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1. Jawaban bapakdr
y = x(x - 6) = x² - 6x
y = x(x - 3)(x - 6) = x(x²-9x+18) = x³-9x²+18x
x³-9x²+18x = x²-6x
x³-10x²+24x = 0
x(x²-10x+24) = 0
x(x-6)(x-4) = 0
x = 0
y = 0(0-6) = 0
x = 6
y = 6(6-6) = 0
x = 4
y = 4(4-6) = -8
titik potong (0,0),(6,0),(4,-8)