Sumbu simetri dari f(x) = (x+6) (x+2) adalah...

f(x) = x^2 + 8x + 12

sumbu simetrinya
x = -b/2a
x = -8/2(1)
x = -8/2
x = -4

Bab Persamaan Kuadrat
Matematika SMP Kelas VIII

f(x) = (x + 6) (x + 2)
f(x) = x² + 8x + 12
a = 1; b = 8; c = 12

sumbu simetri = -b/2a
sumbu simetri = -8/(2 x 1)
sumbu simetri = -4