1. Grafik fungsi f(x) = x3 + 9/2 x2 - 12x +2 turun pada interval... 2. Nilai stationer pada fungsi f(x) = 2x3 - 12x2 + 24x - 3 adalah...

1) turunan < 0
3x² + 9x - 12 < 0
---------------------- ÷3
x² + 3x - 4 < 0
(x + 4)(x - 1) < 0
-4 < x < 1

2) turunan = 0
6x² - 24x + 24 = 0
------------------------ ÷ 6
x² - 4x + 4 = 0
(x - 2)(x - 2) = 0
x = 2
y = 2(2)³ - 12(2)² + 24(2) - 3
= 16 - 48 + 48 - 3
= 13 (nilai stasioner)