tolong bantu dgn caranya

Mr urea = Ar C + Ar O + 2 Ar N + 2 Ar H = 12 + 16 + 2(14) + 2(1) = 60

[ 26 ] V = n × VM = 8 mol × 22,4 L/mol = 179,2 L

[ 27 ] m C = ( Ar C / Mr urea ) × m urea = 12/60 × 50 gr = 10 gr

[ 28 ] m N = ( 2 Ar N / Mr urea ) × m urea = 2(14) / 60 × 50 = 23,33 gr

[ 29 ] 75% C, 25% H
n C : n H = ( m C / Ar C ) : ( m H / Ar H )
= ( 75 / 12 ) : ( 25 / 1 )
= 6,25 : 25 = 1 : 4

RE = CH4

[ 30 ] Mr ( CH2O )n = n ( Ar C + 2 Ar H + Ar O )
60 = n ( 12 + 2(1) + 16 )
60 = 30 n
n = 2

RM = ( CH2O )n = C2H4O2 = CH3COOH