jika f(x)=3x-1 dan g(x)= x^2+4x-5 maka (gof) (x)= A.9x^2+12x-8 B.9x^2+12x-5 C.9x^2+12x-4 D.9x^2+6x-5 E.9x^2+6x-8
Matematika
mellyanavita
Pertanyaan
jika f(x)=3x-1 dan g(x)= x^2+4x-5 maka (gof) (x)=
A.9x^2+12x-8
B.9x^2+12x-5
C.9x^2+12x-4
D.9x^2+6x-5
E.9x^2+6x-8
A.9x^2+12x-8
B.9x^2+12x-5
C.9x^2+12x-4
D.9x^2+6x-5
E.9x^2+6x-8
2 Jawaban
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1. Jawaban keruasriki
g(f(x))
g(3x - 1)
(3x - 1)^2 + 4(3x - 1) - 5
9x^2 - 6x + 1 + 12x - 4 - 5
9x^2 + 6x - 8 -
2. Jawaban Ashiela
f(x) = 3x-1
g(x) = x²+4x-5
(g•f)(x) = g(f(x))
= (3x-1)² + 4(3x-1) - 5
= 9x²-6x+1+12x-4-5
= 9x² + 6x - 8 (E)