Dik: f(x) = x² -2x - 3, g (x) = x + 1 dan h(x) = 3 - 2x (utk soal 1-5) 1. (g+h) (x)= 2. (f+g)(x)= 3. (f-h)(x)= 4. (g.h)(x)= 5. ( \frac{f}{g} ) (x) =

Diketahui : 
f(x) = x² - 2x - 3
g(x) = x + 1
h(x) = 3 - 2x

Nomor 1
------------
(g + h)(x) = g(x) + h(x)
= (x + 1) + (3 - 2x)
= 4 - x

Nomor 2
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(f + g)(x) = f(x) + g(x)
= (x² - 2x - 3) + (x + 1)
= x² - x - 2

Nomor 3
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(f - h)(x) = f(x) - h(x)
= (x² - 2x - 3) - (3 - 2x)
= x² - 6

Nomor 4
-------------
(g.h)(x) = g(x) . h(x)
= (x + 1).(3 - 2x)
= 3x + 3 - 2x² - 2x
= - 2x² + x + 3

Nomor 5
------------
(f/g)(x) = f(x) / g(x)
= (x² - 2x - 3) / (x + 1)
= (x - 3).(x + 1) / (x + 1)
= (x - 3) 

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