tentukanlah nilai dari cot (270-B) jika sin B =2/3 bantuin dong kakak abang :D

sinB = 2/3

(cosB)^2 = 1 - (sinB)^2 = 1 - (2/3)^2 = 1 - 4/9 = 5/9

cosB = akar(5/9)
cosB = 1/3 akar5

cot(270-B) = tanB = sinB/cosB = 2/3 : 1/3 akar5
= 2/3 × 3/akar5
= 2/akar5
atau
= 2/5 akar5