bantu jawab ya teman2 dri no 10-13 pake caranyaa yaa makasiii:)

10.) b. 62,5°

11.) 5x + 90° +x + 90°=360°
6x + 180° = 360°
6x = 360° - 180°
6x = 180°
x = 180°/6
x = 30°

sudut AOC = 90° + x = 90° + 30° = 120°

b. 120°

12.) 40° + 5x° + 3x° = 180°
40° + 8x° = 180°
8x° = 180° - 40°
8x = 140°
x = 140/8
x = 17,5°

sudut ABD = 40° +5x° = 40°+5(17,5) =
40 + 87,5 = 127,5°

c. 127,5°

13) a = 2/3(180-a)
a = 120 - 2/3a
a+ 2/3 a = 120
3/3 a + 2/3 a = 120
5/3 a = 120
5a = 120 x 3
5a = 360
a = 72 °

besar penyiku sudut tsb =
72°+ n = 90°
n = 90° - 72°
n = 18°

A. 18°