tentukan (fog) ^-1 jika f(x)=3x-2dan d(x)=1/2x+3

itu mungkin yg kamu maksud buka d(x) tp g(x) yaa?

diket = f(x) = 3x-2
g(x) = 1/2 x + 3
ditanya = (fog)^-1
jawab
(fog)(x) = f(g(x))
f(1/2x+ 3)
3(1/2x+ 3) - 2
3/2 x + 9 - 2
3x + 9 -2
3x + 6
(fog) ^-1 (x) = 3x + 6
y = 3x + 6
y-6 3x
y-6 / 3 = x
(fog) ^-1 = x-6 /3

semoga membantu :) maaf ya kalau ada yg salah:)