segitiga ABC mempunyai panjang a,b dan c jika a+b=10, sudut a = 30° dan sudut b=50°,panjang sisi b=......

<A = 30
<B = 60
<C = 90
a+b = 10
a = 10-b
b/sin B = a/sin a
b/sin 60 = (10-b)/sin 30
b/(√3/2) = (10-b)/(1/2)
(1/2).b = (10-b)(√3/2)
b/2 = 5√3 - b√3/2
b/2 + b√3/2 = 5√3
(b + b√3)/2 = 5√3
b + b√3 = 10√3
b(1+√3) = 10√3
b = (10√3)/(1+√3) rasionalkan
(10√3)/(1+√3) × (1-√3)/(1-√3)
= (10√3-10.3) / (1-3)
= (10√3 - 30) / -2
= -5√3 + 15
= 15 - 5√3