Jika F(x)=2x²-px²+Qx+4 Q(x) = 2x³+3x²-4x+1 Mempunyai sisa yang sama jika.di bagi (x+1) nilai p+q =

x+1 = 0
x = -1
Q(-1) = 2*-1³ + 3*-1² -4*-1+1 = -2+3+4+1 = 6
Q(-1) = F(-1)
F(-1) = 6
2*-1² -p*-1² +q*-1 +4 = 6
2 -p -q +4 =6
-p-q = 6-4-2
-p-q = 0
p+q = 0