tolong dibantu yah sulit banget

[tex] \lim_{x \to \--3} \frac{x + 3}{(x+3)(x-3)} \\ \\ \lim_{n \to \--3} x-3 \\ \\ = \frac{1}{-3-3} = - \frac{1}{6} [/tex]

lim x+3/x²-9
=lim x+3/(x+3)(x-3)
=lim 1/(x-3)
=1/(-3(-3))
=1/-6
=-1/6