Persamaan garis singgung kurva y= 2x²-3x²-4x+5 dititik yg bergaris 2 adalah.. Mohon bantuannya yah

y = 2x^2 -3x^2-4x + 5, dititik x1 = 2
y1 = f(x) = 2(2)^2 -3(2)^2 -4(2) + 5
= 8 -12 -8 + 5
= -7
m = y' = 4x -6x -4
= 4(2) -6(2) -4
= 8 -12-4
= -8
y -y1 =m (x-x1)
y -(-7) = -8 (x-2)
y+7 = -8x+16
y =-8x-16-7
y =-8x -23
8x +y + 23 = 0