Matematika

Pertanyaan

tolong yah pusing nihh
tolong yah pusing nihh

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1 Jawaban

  • lim x->1 (√x - 1)/(x-1)
    = lim x->1 (√x - 1)/(√x - 1)(√x +1)
    = lim x->1 (√x - 1)/(√x - 1) x 1/(√x +1)
    = lim x->1 1 /( √x + 1 )
    = 1/(√1 + 1)
    = 1/2

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