tentukan nilai dari a.log 400 b.log 144 c.log 0,05 d.log 0,0625 e.log 0,001
Matematika
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Pertanyaan
tentukan nilai dari
a.log 400
b.log 144
c.log 0,05
d.log 0,0625
e.log 0,001
a.log 400
b.log 144
c.log 0,05
d.log 0,0625
e.log 0,001
2 Jawaban
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1. Jawaban Rdd13
a. 2,60
b. 2,15
c. -1,30
d. -1,20
e. -3 -
2. Jawaban khairani347
log 2 =0.301
log 3 = 0.477
log 5 = 0.699
a.log 400 = log 100 x log 4
= 2 + 2 log 2
= 2 + 2 x 0.301
= 2 + 0.601
= 2.601
b.log 144 = log 12²
= 2 log 12
= 2 (log 4 x log 3)
= 2 (2log 2 + 0.477)
= 2 (2 x 0.301 + 0.477)
= 2 (0.602 + 0.477)
= 2 (1.079)
= 2.158
c.log 0.05 = log 5 x log (1/100)
= 0.699 + (-2)
= -1.301
d.log 0.0625 = log 625 x log (1/10000)
= log 5^4 x log (10^(-4))
= 4 log 5 - 4
= 4 x 0.699 - 4
= 2.796 - 4
= -1.204
e.log 0.001 = log 1 x log (1/1000)
= 0 + log(10^(-3)
= -3