Jika f(3-2x) = [tex] (1+3x)^{4} [/tex] Nilai f'(3) = ... A. 6 B. 4 C. 0 D. -4 E. -6

f(3-2x) = (1 + 3x)⁴
misal p = 3 - 2x
2x = 3 - p
x = (3-p)/2
f(p) = (1 + 3(3-p)/2)⁴
f(x) = (1 + 3(3-x)/2)⁴
f(x) = (1 + 9/2 - 3/2x)⁴
f(x) = (11/2 - 3/2x)⁴
f'(x) turunan yah
f'(x) = -3/2(4) (11/2 - 3/2x)³
f'(x) = -6(11/2 - 3/2x)³
f'(3) = -6(11/2 - 3/2(3))³
= -6(11/2 - 9/2)³
= -6(2/2)³
= -6(1)³
= -6(1)
= -6