Matematika

Pertanyaan

Turunan dari y = [tex] (1-x)^{2} (2x+3)[/tex]

2 Jawaban

  • u = (1-x)²
    u' = 2(1-x)
    v = 2x+3
    v' = 2

    (uv)' = u'v+uv'
    = 2(1-x) (2x+3) + (1-x)² (2)
    = (-4x²-2x+6) + (2x²-4x+2)
    = -2x²-6x+8
  • y = (1 - x)^2 (2x + 3)
    = (1 - 2x + x^2)(2x + 3)
    = 2x + 3 - 4x^2 - 6x + 2x^3 + 3x^2
    = 2x^3 - x^2 - 4x + 3
    y' = 6x^2 - 2x - 4

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