Jalannya gimana tolong bantu ?

Tanda '^' artinya pangkat
a = 1/9
{ingat, a^-1 = 1/a}
a = 9^-1
b = 54
b = 9 × 6
c = 4

(a^-4 . b^-1 . c^2) / (a^-6 . b^-3 . c^4)
= (a^-4 . b^-1 . c^2) × (a^-6 . b^-3 . c^4)^-1
{ingat, (a^1 . b^2)^3 = (a^3 . b^6)}
= (a^-4 . b^-1 . c^2) × [(a^-6)^-1 . (b^-3)^-1 . (c^4)^-1]
{ingat, (a^2)^3 = a^6}
= (a^-4 . b^-1 . c^2) × (a^6 . b^3 . c^-4)
= (a^-4 . a^6 . b^-1 . b^3 . c^2 . c^-4)
{ingat, (a^3 . a^4) = a^3+4 = a^7}
= (a^-4+6 . b^-1+3 . c^2-4)
= (a^2 . b^2 . c^-2)
= [(9^-1)^2 . (9×6)^2 . (4)^-2]
{ingat, (a.b)^3 = a^3 . b^3}
= 9^-2 . 9^2 . 6^2 . 4^-2
= 9^-2+2 . 6^2 . 4^-2
= 9^0 . 6^2 . 4^-2
= 1 . 6^2 / 4^2
= 36 / 16
= 18 / 8
= 9 / 4
= 2¼

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