Matematika

Pertanyaan

1. cos (pi/2 - x) tan x =
a. sin x tan x
b. cos x
c. tan x
d. cosec x
e. sec x

2. sec alpha tan2 alpha + sec alpha
a. sec alpha
b. sec2 alpha
c. sec3 alpha
d. cosec alpha
e. cosec2 alpha

3. (tan pi/4 + tan pi/6) / (1 - tan pi/4 tan pi/6)
a. akar 3
b. 2 - akar 3
c. 2 + akar 3
d. 2akar3 - 1
e. 2akar3 +1

1 Jawaban

  • pi = 180
    1) cos (180/2 - x) tan x
    = cos (90-x) tan x
    = sin x tan x

    2) sec a tan²a + sec a
    = sec a (sec² - 1) + sec a
    = sec³a - sec a + sec a
    = sec³a

    3) (tan 180/4 + tan 180/6)/(1 - tan 180/4 tan 180/6)
    = (tan 45 + tan 30)/(1 - tan 45 tan 30)
    = (1 + ⅓√3) / (1 - 1(⅓√3))
    = (3/3 + √3/3) / (3/3 - √3/3)
    = (3+√3)/3 / (3-√3)/3
    = (3+√3)/3 × 3/(3-√3)
    = (3+√3)/(3-√3)
    = (3+√3)/(3-√3) × (3+√3)/(3+√3)
    = (9+6√3+3) / (9-3)
    = (12+6√3) / 6
    = 2+√3

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