Matematika

Pertanyaan

Sederhanakan lah:
A. Log 3 + log 4 + log 5/3 - log 2
B. 2log 32 - 2log 1/64

2 Jawaban

  • A. log (( 3 . 4 . 5/3 )/2)= log 10 = 1
    B. 5 ²log 2 - (-6) ²log 2 = 5+6 = 11
  • A). log 3 + log 4 + log 5/3 - log 2
    = log(3.4) + log 5/3 - log 2
    = log 12 + log 5/3 - log 2
    = log(12.5/3) - log 2
    = log 20 - log 2
    = log(20:2)
    = log 10
    = 1

    B). ²log 32 - ²log 1/64
    = ²log(32:1/64)
    = ²log(32.64/1)
    = ²log 2048
    = ²log 2¹¹
    = 11.²log 2
    = 11.1
    = 11

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