Ditentukan f(x) = (8x+2 )/(x-1), rumus invers f(x) adalah . . . a. (x+2 )/(x-8) b. (x+2 )/(x-3) c. (x+2 )/(x+8) d. (x-7 )/(x+3) e. (-x+7 )/(x-3)

y = (8x+2)/(x-1)
xy - y = 8x+ 2
xy - 8x = 2 + y
x (y-8) = 2+y
x = (2+y)/(y-8)
f^-1(x) = (2+x)/(x-8)

jawabannya A

f (x) = (8x + 2) / (x - 1)
Misal :
y = f (x)

f (x) = (8x + 2) / (x - 1)
y = (8x + 2) / (x - 1)
xy - y = 8x + 2
xy - 8x = y + 2
x (y - 8) = y + 2
x = (y + 2) / (y - 8)
f⁻¹(x) = (x + 2) / (x - 8)

Jawabannya adalah A. (x + 2) / (x - 8)