diketahui prisma tegak dengan alas segitiga siku siku, panjang AC= 24 AB= 25 dan volum prisma = 336cm³.tinggi prisma adalah

BC² = 25² - 24²
BC² = 49
BC = 7 cm

volume prisma = luas alas * t prisma
336 = 1/2 * 7 * 24 * t
84t = 336
t = 4 cm

BC = √AB²-AC²
BC = √25²-24²
BC = √625-576
BC = √49
BC = 7 cm

V Prisma = L alas × t Prisma
336 = L∆ ×t Prisma
336 = ½×a×t × t Prisma
336 = ½×24×7 × t Prisma
336 = 12×7 × t Prisma
336 = 84 × t Prisma
t Prisma = 336/84 = 4 cm