Fisika

Pertanyaan

kak bantuin please no.9 dan 10...
kak bantuin please no.9 dan 10...

1 Jawaban

  • Nomor 9
    -----------
    fob = 100 cm
    M min = 20 kali
    Tanya :
    Jarak lensa obyektif dan okuler, d = ___?

    Jawab :
    Step 1
    ---------
    Cari fok = ___?
    M min = fob / fok
    20 = 100 / fok
    fok = 50 cm

    Step 2
    ---------
    Cari d = __?
    d = fob + fok
    d = 100 + 50
    d = 150 cm

    Nomor 10
    --------------
    Suhu awal, T1 = 45 derajat C
    Suhu akhir, T2 = 85 derajat C
    Beda suhu, delta T = T2 - T1 = 85 - 45 = 40 derajat C

    Panjang akhir, L = 50,02 cm
    Koef muai panjang, alfa = 1 x 10^-5 / derajat C

    Tanya :
    Panjang awal baja, Lo = ___?

    Jawab :


    L = Lo.(1 + alfa. Delta T)

    50,02 = Lo.(1 + 10^-5. 40)
    50,02 = Lo.(1 + 4.10^-4)
    50,02 = Lo.(1 + 0,0004)
    50,02 = Lo.(1,0004)

    Lo = 50,02 / 1,0004

    Lo = 50 cm

    ___________________
    )|(
    FZA