11 dan 12 gimana kak .....

Nomor 11
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Diketahui :
Panjang, p = 25 cm
Lebar, l = 20 cm
Luas awal, Ao = p x l = 25 x 20 = 500 cm^2

Suhu awal, T1 = 0 derajat C
Suhu akhir, T2 = 40 derajat C
BEFA suhu, delta T = (T2 - T1) = 40 derajat C

Koef muai panjang, alfa = 17 x 10^-6 / derajat C

Tanya :
Luas akhir, A = ___?

Jawab :
Step 1
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Hitung pertambahan luas
Delta A = Ao • beta • delta T
= Ao • 2.alfa • delta T
= 500• 2. 17.10^-6• 40
= 68 x 10^-2
= 0,68 cm^2

Step 2
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Luas akhir,
A = Ao + delta A
A = 500 + 0,68
A = 500,68 cm^2


Nomor 12
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P1 = 1 atm
V1 = 0,5 Liter
T1 = 27 deajat C = 300 K

Menjadi
T2 = 327 derajat C = 600 K
P2 = 2 atm
V2 = ___?

Jaaab :
P1.v1 / T1 = P2.v2 / T2

1. 0,5 / 300 = 2. V2 / 600
1 / 600 = 2. V2 / 600

1 = 2. V2

V2 = 0,5 liter


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