jika f(x) = x2 - 2x + 4 dan g(x) = x+3 maka nilai x yang memenuhi (g 0 f)(x) = 6 adalah

( g o f)(x) = g(f(x))

g(f(x)) = (x^2 -2x + 4) + 3
6 = x^2 - 2x + 7
x^2 -2x + 7 - 6 = 0
x^2 - 2x + 1 = 0
(x - 1)(x - 1) = 0

x - 1 = 0
x = 1

Nilai x = 1

(g○f)(x) = g○(f(x)) = 6
= g○(x^2 - 2x + 4) = 6
= x^2 - 2x + 4 + 3 = 6
= x^2 - 2x + 7 = 6
= x^2 - 2x + 7 - 6 = 0
= x^2 - 2x + 1 = 0
= (x - 1)(x - 1) = 0
x - 1 = 0
x = 1
maka nilai x yg memenuhi (g○f)(x) = 6 adalah 1