Matematika

Pertanyaan

nilai lim mendekati 2 dari x²+x-6/1-√(x²-3)

1 Jawaban

  • Lim (x²+x-6)(1+√x²-3) / (1-√x²-3)(1+√x²-3)
    x→2

    Lim (x-2)(x+3)(1+√x²-3) / (1 - (x²-3)
    x→2

    Lim (x-2)(x+3)(1+√x²-3) / (4 - x²)
    x→2

    Lim (x-2)(x+3)(1+√x²-3) / (2-x)(2+x)
    x→2

    Lim(x-2)(x+3)(1+√x²-3) / -(x-2)(2+x)
    x→2

    = (2+3)(1+√2²-3) / -(2+2)
    = (5) (1+√1) / (-4)
    = (5) (2) / (-4)
    = - 10/4
    = - 5/2

    Semoga berguna +_+

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