Matematika

Pertanyaan

1. (x-4) (x+3) (x-1) >= 0

2. X+9 >= 3
2-3

3. Akar (x+3) (x-2) > 6

1 Jawaban

  • 1) (x - 4)(x + 3)(x - 1) ≥ 0
    - - - -- + + + + - - - - - + + +
    -------•---------•--------•---------
    ````````-3 ````````` 1 ```````` 4
    -3 ≤ x ≤ 1 atau x ≥ 4

    3) √(x+3)(x-2) > 6
    kuadrat kan kedua ruas
    (x + 3)(x - 2) > 6²
    x² + x - 6 > 36
    x² + x - 6 - 36 > 0
    x² + x - 42 > 0
    (x + 7)(x - 6) > 0
    + + + - - - - - + + +
    ------•--------•--------
    ```````-7 ````````6
    x < -7 atau x > 6
    syarat akar ≥ 0
    (x + 3)(x - 2) ≥ 0
    + + + - - - - - + + +
    -------•-------•--------
    ```````-3 ``````` 2
    x ≤ -3 atau x ≥ 2
    jadi hp
    x < -7 atau x > 6

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