1. (x-4) (x+3) (x-1) >= 0 2. X+9 >= 3 2-3 3. Akar (x+3) (x-2) > 6
Matematika
putry1112
Pertanyaan
1. (x-4) (x+3) (x-1) >= 0
2. X+9 >= 3
2-3
3. Akar (x+3) (x-2) > 6
2. X+9 >= 3
2-3
3. Akar (x+3) (x-2) > 6
1 Jawaban
-
1. Jawaban bapakdr
1) (x - 4)(x + 3)(x - 1) ≥ 0
- - - -- + + + + - - - - - + + +
-------•---------•--------•---------
````````-3 ````````` 1 ```````` 4
-3 ≤ x ≤ 1 atau x ≥ 4
3) √(x+3)(x-2) > 6
kuadrat kan kedua ruas
(x + 3)(x - 2) > 6²
x² + x - 6 > 36
x² + x - 6 - 36 > 0
x² + x - 42 > 0
(x + 7)(x - 6) > 0
+ + + - - - - - + + +
------•--------•--------
```````-7 ````````6
x < -7 atau x > 6
syarat akar ≥ 0
(x + 3)(x - 2) ≥ 0
+ + + - - - - - + + +
-------•-------•--------
```````-3 ``````` 2
x ≤ -3 atau x ≥ 2
jadi hp
x < -7 atau x > 6