integral dari 4sin5x.cos3x dx =

[tex] \int\limits \,4 sin 5x cos x dx [/tex]
inget rumus sin A . cos B = [tex] \frac{1}{2} [/tex] {sin (A+B) + sin (A-B)}
= [tex] \int\limits {} \, 4 \frac{1}{2} {sin (5x+x) + sin (5x-x)} dx [/tex]
= [tex] \int\limits {4} \frac{1}{2} (sin 6x + sin 4x) \, dx [/tex]
= [tex]2 ( - \frac{1}{6} cos 6x - \frac{1}{4} cos 4x )[/tex] + C
=