Matematika

Pertanyaan

Jika f(2x - 1) = 8x² - 2 , nilai f' (-2) =

1 Jawaban

  • f(2x - 1) = 8x^2 - 2
    2f'(2x - 1) = 16x
    f'(2x - 1) = 8x
    f'(2(-1/2) - 1) = 8(-1/2)
    f'(-1-1) = -8/2
    f'(-2) = -4

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