jika diketahui harga ksp AgCO3 = 8 x 10^-12, berapakah massa Ag2CO3 yang larut dalam 100ml air murni ? (Ar Ag = 108; C = 12; O = 16 )

Ag2co3 => ag2+ + co3 2-
s ~s ~ s
Ksp = (s) x (s)
8 x 10^-12 = s^2
s = √8 x 10^-12
s = 2,8 x 10^-6

s = M
M = gr / mr x 1000/ ml
2,8 x 10^-6 = gr / 276 x 1000/10
gr = 7,7 x 10^-6 gr