cos 150 derajat + sin 45 derajat + 1/2 cot(-330 derajat)=.......
Matematika
teguh021
Pertanyaan
cos 150 derajat + sin 45 derajat + 1/2 cot(-330 derajat)=.......
1 Jawaban
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1. Jawaban hafidaagustini
Cos 150 + Sin 45 + [tex] \frac{1}{2} [/tex] cot (-330) =
-(Cos 30) + [tex] \frac{1}{2} \sqrt{2} [/tex] + [tex] \frac{1}{2} x \frac{1}{(tan 30)} [/tex]
-[tex] \frac{1}{2} \sqrt{3} [/tex] + [tex] \frac{1}{2} \sqrt{2} [/tex] + [tex] \frac{1}{2} \sqrt{3} [/tex] = [tex] \frac{1}{2} \sqrt{2} [/tex]