luas permukaan limas berbentuk persegi 360cm pangkat 2. jika panjang rusuk alas 10 cm maka tinggi limas itu adalah.....cm

a. LP = L.alas + 4(LΔ)
b. C² = A² + B²

360 = 100 + 4(1/2 x 10 x t)
360 = 100 + 20t
20t = 360 - 100
20t = 260
t = 13 Cm

T. Limas = x
x² = 13² - 5²
x² = 169 - 25
x² = 144
x = 12 Cm   

Dik :
Lp = 360 cm^2
s = 10 cm

Dit :
t = ...?

Penye :
La = 10 cm . 10 cm
La = 100 cm^2 

Lp = La . 4 . L segitiga
360 cm^2 = 100 cm^2 . 4 (1/2 . 10 . t)
360 cm^2 = 100 cm^2 . 4 . 5t cm
360 cm^2 = 100 cm^2 . 20t cm
100 cm^2 . 20t cm = 360 cm^2
20t cm = 360 cm^2 - 100 cm^2
20t cm = 260 cm^20
t = 260/20
t = 13 cm