Matematika

Pertanyaan

tolong dibantu jwb plus caranya please ...
tolong dibantu jwb plus caranya please ...

2 Jawaban

  • AB = √7²-2²
    AB = √49 - 4
    AB = √45
    AB = √9 × 5
    AB = 3√5 cm

    Luas Bidang OABC
    = 2 x  L
    ∆OAB
    = 2 x (1/2 x a x t)
    = 2 x (1/2 x 2 x 3
    √5)
    = 2 x (3√5)
    = 6√5 cm² (C)

    Semoga Membantu!!!


  • OB = 7 cm
    OA = OC = 2 cm
    BC = AB = √(OB² - OA²)
    = √(7²-2²)
    = √(49-4)
    = √45 = 3√5 cm

    Luas OABC
    = luas OAB + luas OBC
    = (½×OA×AB) + (½×OC×BC)
    = (½×2×3√5) + (½×2×3√5)
    = 3√5 + 3√5
    = 6√5 cm²